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如何实现二倍频? [复制链接]

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离线yangtse88
 
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只看楼主 倒序阅读 0楼 发表于: 2007-05-22
rt
给个思路
离线BG8SF
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4684
只看该作者 1楼 发表于: 2007-05-22
次级放大器的谐振点直接调谐在二次谐波上就行了!
输出再加虑波器!
离线小比尔/5
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2582
只看该作者 2楼 发表于: 2007-05-22
'
rt
给个思路
'
锁相环
二极管削波 选频
丙类放大 选频
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479
只看该作者 3楼 发表于: 2007-05-25
无源双平衡混频器有用做2倍频器的接法。
离线huangzs
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只看该作者 4楼 发表于: 2007-05-25
mc1496也可实现
离线ironman
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1915
只看该作者 5楼 发表于: 2007-05-25
你要倍频数字信号还是模拟信号?频率低的话,微分一下,把上下跳沿取出,再倒像上跳沿,与下跳沿合并即可.
离线yangtse88
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11
只看该作者 6楼 发表于: 2007-05-26
'
你要倍频数字信号还是模拟信号?频率低的话,微分一下,把上下跳沿取出,再倒像上跳沿,与下跳沿合并即可.
'
要倍频的信号是数字信号,10k左右
离线QSL599
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294
只看该作者 7楼 发表于: 2007-05-26
倍频器。这是e文说明: this frequency doubler using a single 4069 hex inverter ic, a frequency doubler can be constructed to give an output pulse train whose frequency is twice that of a squarewave input signal. the signal is applied to the input of n1. it should be a squarewave with a duty-cycle of approximately 50% at level compatible with cmos logic (3-15v peak to peak depending on supply voltage). the input signal is buffered and inverted by n1, and inverted again by n2, so the outputs a and b of n1 and n2 are squarewave signals 180° out of phase. the output of n1, is differentiated by c1 and r1 and the output of n2 is differentiated by c2 and r2, giving two spike waveforms of c and d, 180° out of phase. the signals are buffered, inverted and shaped by n3 and n4. these are then combined in a nor gate consisting of d1, d2, r3 and n5, and finally inverted by n6 to give the frequency twice that of the input signal. the circuit will operate over a wide frequency range. with the component values shown the width of pulses in e and f point is about 500ns, so the duty cycle of the output will be 50% when the frequency is 1mhz, when the input frequency is 500khz.by a.m. bosschaert
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离线QSL599
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只看该作者 8楼 发表于: 2007-05-26
再上一图:4011倍频
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离线ironman
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1915
只看该作者 9楼 发表于: 2007-05-27
对了,就是微分后取两个边沿.