PHPWIND
HELLOCQ
UID:38639
UID:38045
UID:2109
UID:17497
UID:6156
UID:151
UID:2714
UID:878
UID:9962
UID:5737
UID:5788
UID:23724
算一下吧功率:p=u*u/r原电压:u1=110v现电压:u2=220v=2u1原功率:p1=u1*u1/r如果不串二极管直接接220v时功率:p'=u2*u2/r=4p1串二极管再接220v时功率:p2=(u2*u2/r)/2=2u1*u1/r=2p1比原来大一倍.
UID:5944
UID:22
没有必要绕这么麻烦,110v额定电压的纯电阻负载,在220v上功率为4倍额定值,串一个二极管,通电时间减半,此时功率为2倍额定值。